Просто как шпаргалка, Xml сериализация, если память отобьет:
// This is the test class we want to
// serialize:[Serializable()]public class TestClass
{ private string someString;
public string SomeString
{ get { return someString; } set { someString = value; } }
private List<string> settings = new List<string>();
public List<string> Settings
{ get { return settings; } set { settings = value; } }
// These will be ignored [NonSerialized()] private int willBeIgnored1 = 1;
private int willBeIgnored2 = 1;
}
// Example code
// This example requires:// using System.Xml.Serialization;// using System.IO;
// Create a new instance of the test classTestClass TestObj = new TestClass();
// Set some dummy valuesTestObj.SomeString = "foo";
TestObj.Settings.Add("A");
TestObj.Settings.Add("B");
TestObj.Settings.Add("C");
#region Save the object
// Create a new XmlSerializer instance with the type of the test classXmlSerializer SerializerObj = new XmlSerializer(typeof(TestClass));
// Create a new file stream to write the serialized object to a fileTextWriter WriteFileStream = new StreamWriter(@"C:\test.xml");
SerializerObj.Serialize(WriteFileStream, TestObj);
// CleanupWriteFileStream.Close();
#endregion
/*The test.xml file will look like this: <?xml version="1.0"?><TestClass xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <SomeString>foo</SomeString> <Settings> <string>A</string> <string>B</string> <string>C</string> </Settings></TestClass>
*/
#region Load the object
// Create a new file stream for reading the XML fileFileStream ReadFileStream = new FileStream(@"C:\test.xml", FileMode.Open, FileAccess.Read, FileShare.Read);
// Load the object saved above by using the Deserialize functionTestClass LoadedObj = (TestClass)SerializerObj.Deserialize(ReadFileStream);
// CleanupReadFileStream.Close();
#endregion
// Test the new loaded object:MessageBox.Show(LoadedObj.SomeString);
foreach (string Setting in LoadedObj.Settings) MessageBox.Show(Setting);
